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JNTU B.Tech II ELECTRICAL AND ELECTRONICS ENGINEERING Previous Question Paper (March - 2022 - R13)

B.Tech | II | II | R13 | March - 2022

Answer PaperPaper Code: 114BDMaximum Marks: 75Time: 3 Hours

Answer any five questions

All questions carry equal marks

Main

115 marks
a

Classify Network elements and give their volt-ampere relations.

8 marks

Answer

Network elements are broadly classified into two categories: Active and Passive elements.

Active Elements: These elements are capable of delivering energy to the network. They act as sources of energy. Examples include voltage sources and current sources.

Volt-Ampere relations:

Independent Voltage Source: v(t) = Vs
Independent Current Source: i(t) = Is

Passive Elements: These elements are capable of receiving or storing energy but cannot generate it. Examples include resistors, inductors, and capacitors.

Volt-Ampere relations:

Resistor: v(t) = R · i(t)
Inductor: v(t) = L · di(t)/dt
Capacitor: i(t) = C · dv(t)/dt

Elements can also be classified as Linear/Non-linear (based on superposition principle), Bilateral/Unilateral (based on direction of current), and Time-invariant/Time-variant (based on parameter constancy over time).

b

Derive the expressions for the equivalent inductance when two inductances are connected in: (i) Series adding (ii) Series opposition (iii) Parallel.

7 marks

Answer

Consider two inductors L1 and L2 with mutual inductance M.

(i) Series Adding: When connected in series such that flux produced by both aids each other, the total inductance is:

Leq = L1 + L2 + 2M

(ii) Series Opposition: When connected such that flux produced by one opposes the other, the total inductance is:

Leq = L1 + L2 - 2M

(iii) Parallel: For two inductors in parallel with mutual coupling M, the equivalent inductance is derived from the voltage balance equations:

Leq = (L1L2 - M2) / (L1 + L2 ± 2M)

The sign in the denominator depends on whether the coupling is additive or subtractive.

215 marks
a

Explain the basic principle of PMMC instruments and compare its performance with permanent magnet moving iron instruments.

7 marks

Answer

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b

State and explain Kirchhoff’s laws with an example.

8 marks

Answer

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315 marks
a

Explain the working principle of DC Generator.

8 marks

Answer

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b

A 220V, 4-pole, wave connected dc series motor has armature and field resistances of 0.15 Ω and 0.85 Ω respectively. The armature of motor has 60 conductors per pole. The flux developed in the air gap is 20mWb. Find the speed of the motor.

7 marks

Answer

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415 marks
a

What is meant by Back EMF? Explain the principle of torque production in a dc motor.

8 marks

Answer

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b

Calculate the voltage induced in the armature winding of a 4-pole, lap wound DC machine having 728 active conductors and running at 1800 rpm. The flux per pole is 30 mwb.

7 marks

Answer

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515 marks
a

Derive the EMF equation of Transformer.

8 marks

Answer

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b

A single phase transformer has 400 primary and 1000 secondary turns. The net cross sectional area of the core is 60 cm2. If the primary winding is connected to a 50 Hz supply at 520V, Calculate (i) Peak value of flux density in the core (ii) Voltage induced in the secondary winding (iii) Transformation ratio?

7 marks

Answer

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615 marks
a

Explain the principle of operation of a three phase induction motor with a neat sketch.

8 marks

Answer

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b

A 230/400 V single phase transformer has 800 turns on primary. The maximum flux density in the core is 1.5 Wb/m2. Calculate the number of turns on secondary, area of cross section and maximum flux in the core.

7 marks

Answer

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715 marks
a

Explain the working of n-p-n and p-n-p transistors.

8 marks

Answer

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b

With neat sketch and waveforms, explain the operation of the half wave rectifier?

7 marks

Answer

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815 marks
a

Discuss how to measure the voltage, current and frequency with CRO.

7 marks

Answer

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b

Explain the process of electrostatic and magnetic deflections in CRO.

8 marks

Answer

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