JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech III FINITE ELEMENT METHODS Previous Question Paper (March - 2021 - R18)

B.Tech | III | III-I | R18 | March - 2021

Answer PaperPaper Code: 155BJMaximum Marks: 75Time: 3 Hours

Answer any five questions

All questions carry equal marks

Main

115 marks
a

What are the approximate solutions? Explain Raleigh-Ritz method.

7 marks

Answer

Approximate solutions are numerical or analytical techniques used to find a function that satisfies a differential equation and its boundary conditions with reasonable accuracy, even when an exact closed-form solution is impossible or computationally prohibitive. These methods typically involve assuming a trial function with unknown coefficients and minimizing an error functional.

The Raleigh-Ritz method is a variational technique used to find approximate solutions for boundary value problems by minimizing the total potential energy of the system. The steps are:

  1. Assume an approximate solution in the form of a trial function, typically a linear combination of basis functions: Φ(x) = Φ₀(x) + Σ cᵢψᵢ(x), where Φ₀ satisfies the non-homogeneous boundary conditions and ψᵢ satisfy the homogeneous boundary conditions.
  2. Formulate the total potential energy functional Π for the system.
  3. Substitute the trial function into the functional Π.
  4. Minimize the functional with respect to the unknown coefficients by setting the partial derivatives to zero: ∂Π/∂cᵢ = 0 for i = 1, 2, ..., n.
  5. Solve the resulting system of linear algebraic equations for the coefficients cᵢ.
b

Solve the differential equation

(d2Φ/dx2) + Φ + x = 0, 0 ≤ x ≤ 1

Subjected to the boundary conditions Φ(0) = Φ(1) = 0 using Galerkin method.

8 marks

Answer

Given the differential equation (d²Φ/dx²) + Φ + x = 0 with Φ(0) = 0 and Φ(1) = 0. We assume an approximate solution of the form Φ(x) = c₁x(1-x) = c₁(x - x²), which satisfies the boundary conditions.

The residual R(x) is defined as:

R(x) = (d²Φ/dx²) + Φ + x

Substituting Φ(x) = c₁(x - x²) and d²Φ/dx² = -2c₁:

R(x) = -2c₁ + c₁(x - x²) + x = c₁(x - x² - 2) + x

According to the Galerkin method, the integral of the residual weighted by the basis function must be zero:

∫₀¹ R(x) * (x - x²) dx = 0
∫₀¹ [c₁(x - x² - 2) + x] * (x - x²) dx = 0
c₁ ∫₀¹ (x - x² - 2)(x - x²) dx + ∫₀¹ x(x - x²) dx = 0

Evaluating the integrals:

∫₀¹ (x² - 2x³ + x⁴ - 2x + 2x²) dx = ∫₀¹ (x⁴ - 2x³ + 3x² - 2x) dx = [x⁵/5 - x⁴/2 + x³ - x²]₀¹ = 1/5 - 1/2 + 1 - 1 = -3/10
∫₀¹ (x² - x³) dx = [x³/3 - x⁴/4]₀¹ = 1/3 - 1/4 = 1/12

Substituting back:

c₁(-3/10) + 1/12 = 0 => c₁ = (1/12) * (10/3) = 10/36 = 5/18

The approximate solution is Φ(x) = (5/18)(x - x²).

2

Find the deflection at the load and slopes at the ends for the steel shaft shown in figure 1. Consider the shaft to be simply supported at bearings at A and B.

15 marks

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3

Derive shear force and bending moment relations for beam element.

15 marks

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4

Derive the Stiffness matrix for a CST element using Potential Energy approach.

15 marks

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5

An axisymmetric body with linearly distributed load on conical surface is shown in figure 2. Determine the equivalent point loads at nodes 2, 4 and 6.

15 marks

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6

Derive shape functions and element stiffness matrix for 4 noded isoparametric quadrilateral elements.

15 marks

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7

Find the temperatures of circular fin made of pure copper (k= 350 W/m °C). The base of the fin is held at 75°C and atmospheric temperature is 27°C. The fin length is 5 cm and the diameter is 0.5 cm. the convective heat transfer coefficient h is 200 W/m² °C. The tip at the end of the fin is insulated.

15 marks

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8

How can you find eigen values and eigen vectors for bar element? Explain with simple example.

15 marks

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This page contains the question paper of FINITE ELEMENT METHODS from JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD for B.Tech AE III III-I, March - 2021, R18.

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