JNTU

JNTU B.Tech III FLIGHT MECHANICS II Previous Question Paper (February - 2022 - R13)

B.Tech | III | I | R13 | February - 2022

Answer PaperPaper Code: 115BYMaximum Marks: 75Time: 3 Hours

Answer any five questions

All questions carry equal marks

Main

1

Derive the equations for maneuverability – the elevator angle and control force required to hold the airplane in a steady pull-up with load factor.

15 marks

Answer

For a steady pull-up maneuver at a constant load factor n, the airplane undergoes a circular motion with a normal acceleration an = (n-1)g. The equations of motion in the normal direction and about the center of gravity are used to determine the required elevator deflection and stick force.

The normal force equation is L - W = (W/g)V(q), where q = (n-1)g/V is the pitch rate. Substituting L = nW, we obtain the lift requirement. The pitching moment equation about the center of gravity is Mcg = Iy(dθ/dt) = 0 for a steady pull-up, implying the sum of moments must be zero: Mac + L(xcg - xac) + Mtail = 0.

The elevator angle to trim δe is derived by accounting for the increased angle of attack required to generate n times the weight. The total lift is L = CL(1/2)ρV2S. The elevator angle δe is given by:

δe = [Cm,ac + CL(h - hac) + (CL,αα + CL,δeδe)(lt/c)] / [-(Cm,δe)]

Substituting the load factor n, where CL = nW / (1/2)ρV2S, the elevator angle required to maintain the maneuver is:

δe = (1/Cm,δe) * [Cm,0 + CL(h - hac) + (CL,ααt + CL,δeδe)(VH)]

The control force Fs is proportional to the elevator deflection and the aerodynamic hinge moment. Since the hinge moment H = Ch(1/2)ρV2Sece, and Ch = Ch0 + Chααt + Chδeδe, the stick force is expressed as:

Fs = G * [Ch0 + Chααt + Chδeδe] * (1/2)ρV2Sece

where G is the mechanical advantage of the control system. In a steady pull-up, the stick force per g is a critical parameter defined by the rate of change of stick force with respect to the load factor n, representing the pilot's effort to maintain the maneuver.

2

Discuss in detail about the power effects on longitudinal static stability with neat sketches.

15 marks

Answer

The power effects on longitudinal static stability refer to the influence of the propulsion system (propeller or jet engine) on the aircraft's pitching moment characteristics. These effects are primarily categorized into direct effects of the thrust vector and indirect aerodynamic effects caused by the slipstream or exhaust flow.

The total pitching moment about the center of gravity is modified by the thrust as follows:

Cm = Cm,0 + Cm,αα + Cm,δeδe + Cm,T

The term Cm,T represents the contribution of thrust, which depends on the thrust magnitude, the vertical distance between the thrust line and the center of gravity (thrust offset), and the angle of the thrust line relative to the longitudinal axis. If the thrust line is above the center of gravity, an increase in power creates a nose-down (negative) pitching moment, which is stabilizing. Conversely, if the thrust line is below the center of gravity, it creates a nose-up (positive) moment, which is destabilizing.

Key power effects include:

  • Direct Thrust Effect: A thrust line passing below the center of gravity induces a destabilizing nose-up moment as power increases. This effectively reduces the static margin of the aircraft.
  • Propeller Normal Force Effect: At non-zero angles of attack, the propeller disk experiences a normal force that acts at the propeller plane. This force creates a pitching moment that is generally destabilizing as the angle of attack increases.
  • Slipstream Effect: The high-velocity air from the propeller flows over the wing and the horizontal tail. This increases the dynamic pressure at the tail, which can enhance the effectiveness of the horizontal stabilizer, but it also changes the downwash angle at the tail. The net effect depends on the relative geometry of the wing, tail, and propeller.
  • Nacelle/Exhaust Effect: For jet aircraft, the exhaust flow can induce changes in the pressure distribution over the rear fuselage, potentially altering the tail's contribution to stability.

In summary, the longitudinal stability derivative Cm,α is modified by power. A design where the thrust line is positioned to counteract the destabilizing effects of the propeller normal force and slipstream is preferred to maintain consistent handling qualities across different power settings.

3

Derive the axial, normal force components and pitching moment with respect to the flight speed, angle of attack.

15 marks

Answer

Sign in to view the complete answer paper.

4

Derive the equations for side force, rolling moment and yawing moment with respect to sideslip.

15 marks

Answer

Sign in to view the complete answer paper.

515 marks
a

Explain Aerodynamic and mass balancing of control surfaces.

7 marks

Answer

Sign in to view the complete answer paper.

b

Write short note on Control tabs- types, their function and construction.

8 marks

Answer

Sign in to view the complete answer paper.

6

Derive the neutral point equation for stick free condition from the first principles.

15 marks

Answer

Sign in to view the complete answer paper.

7

Explain the position and orientation of an aircraft relative to earth and describe it in terms of Euler’s angles.

15 marks

Answer

Sign in to view the complete answer paper.

8

Define dynamic stability with examples and obtain the solutions to the stability quartic of the linearized equations of motion.

15 marks

Answer

Sign in to view the complete answer paper.

About this paper

This page contains the question paper of FLIGHT MECHANICS II from JNTU for B.Tech AE III I, February - 2022, R13.

For the solved question paper with answers, switch to the Answer Paper tab.

Other papers in FLIGHT MECHANICS II

Loading Question Papers

Fetching data from database...