Jawaharlal Nehru Technological University Hyderabad
Jawaharlal Nehru Technological University Hyderabad B.Tech I ENGINEERING MECHANICS Previous Question Paper (May - 2018 - R16)
Note: Part A is compulsory (25 marks). Part B consists of 5 Units. Answer any one full question from each unit (10 marks each).
Part A
Answer all parts:
Answer
- Coplanar forces: Forces acting in the same plane.
- Non-coplanar forces: Forces acting in different planes.
- Concurrent forces: Forces whose lines of action pass through a single point.
- Parallel forces: Forces whose lines of action are parallel to each other (like or unlike).
- Collinear forces: Forces whose lines of action lie on the same straight line.
- General force system: Forces that are neither concurrent nor parallel.
Answer
Given the tension magnitude |T| = 2 kN, the vector expression is represented as T = T * u, where u is the unit vector along the direction of the cable. If the coordinates of A and the point of application are known, the vector is T = (T_x)i + (T_y)j + (T_z)k, where T_x, T_y, and T_z are the components of the 2 kN force along the respective axes.
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Part B
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