Jawaharlal Nehru Technological University Hyderabad

Jawaharlal Nehru Technological University Hyderabad B.Tech III Year STRUCTURAL ENGINEERING - II (STEEL) Previous Question Paper (August - 2022 - R18)

B.Tech | III Year | II Semester | R18 | August - 2022

Answer PaperPaper Code: 156CYMaximum Marks: 75Time: 3 hours

Answer any five questions. All questions carry equal marks. Note: Use of IS 800:2007, IS 875 (part 3) and steel tables are allowed.

Main

1

Design the seat angle connection between the beam ISMB 250 and column ISHB 250 for a reaction from beam equal to 85 kN. Use M16 black bolt of property class 4.6 and grade Fe410 steel with fy = 250 MPa.

15 marks

Answer

To design the seat angle connection for a reaction of 85 kN, we follow these steps:

  1. Bolt Capacity: For M16 black bolts (Grade 4.6), the ultimate strength fub = 400 MPa. The shear capacity Vdsb = (fub / (sqrt(3) * γmb)) * Anb. With Anb = 157 mm², Vdsb = (400 / (1.732 * 1.25)) * 157 = 29.01 kN. The bearing capacity Vdpb = 2.5 * kb * d * t * fu / γmb. Assuming standard edge/pitch distances, Vdpb is typically higher than shear capacity; thus, shear governs.
  2. Number of Bolts: Required bolts = 85 / 29.01 = 2.93. Provide 4 bolts in the column flange to ensure stability.
  3. Seat Angle Selection: Use ISA 100x100x10 mm. The length of the angle is taken as the width of the beam flange (125 mm). The load is assumed to be distributed over a length b = (width of beam flange / 2) + 10 mm.
  4. Moment Calculation: The bending moment M = R * (a - b/2), where 'a' is the length of the outstanding leg. Check the moment capacity of the angle: Md = (β * Ze * fy) / γm0. Ensure the thickness of the angle is sufficient to resist this moment.
  5. Cleat Angle: Provide a top cleat angle (e.g., ISA 60x60x6 mm) to provide lateral restraint to the beam top flange, though it is not designed to carry the vertical reaction.

The connection is safe provided the angle thickness satisfies the bending requirement and the bolts are spaced according to IS 800:2007 requirements (minimum pitch 2.5d and edge distance 1.5d0).

2

Design a tension member to carry an axial factored load of 500kN. Use a double angle rolled steel section connected (at site) to each side of a gusset plate of 10mm thick using 20mm diameter bolts of grade 4.6.

15 marks

Answer

To design a tension member carrying a factored load of 500 kN using double angles back-to-back on either side of a 10 mm gusset plate, we proceed as follows:

1. Design Strength Requirement: The design strength of the member must be at least 500 kN. Assuming the design is governed by the gross section yielding, the required gross area Ag is calculated using the yield strength of steel (fy = 250 MPa) and a partial safety factor (γm0 = 1.10):

Ag,req = (Tdg × γm0) / fy = (500 × 103 × 1.10) / 250 = 2200 mm2

2. Section Selection: For a double angle section, the area of one angle should be at least 1100 mm2. Selecting two ISA 75x75x8 mm (A = 1138 mm2 each, total Ag = 2276 mm2).

3. Bolt Design: For 20 mm diameter bolts (grade 4.6, fub = 400 MPa), the shear capacity Vdsb and bearing capacity Vdpb are calculated. Assuming a standard pitch of 50 mm and edge distance of 30 mm, the capacity per bolt is determined. With a 10 mm gusset plate, the bearing capacity is usually the limiting factor.

4. Net Section Rupture: The design strength Tdn is checked using the net effective area Ane, considering the reduction factor β for out-of-plane connections:

Tdn = (0.9 × Ane × fu) / γm1 + (β × Ago × fy) / γm0

5. Verification: Ensure the slenderness ratio (λ = L/rmin) does not exceed 300 for members under tension. Check that the chosen section satisfies both the yielding and rupture criteria, and that the bolt group capacity exceeds 500 kN.

3

A beam simply supported over an effective span of 7m, carries a uniformly distributed load of 50kN/m inclusive of its own weight. The depth of the beam is restricted to 450mm. Design the beam, assuming that the compression flange of the beam is laterally supported by a floor construction. Take fy = 250 N/mm² and E = 2 × 10⁵ N/mm². Assuming width of the support as 230mm.

15 marks

Answer

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4

Design a bearing stiffener for a welded plate girder with the following specifications: Web = 1000mm × 6mm thick; Flanges = 2 Nos. of 350 × 20mm plate on each side; Support reaction = 350kN; Width of the support = 300mm.

15 marks

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5

Design a gantry girder to be used in an industrial building carrying an EOT crane for the following data: Crane capacity = 200 kN; Total self-weight of all components = 240 kN; Minimum approach at the crane hook of gantry girder = 1.2m; Wheel base = 3.5m; C/C distance between gantry rails = 16m; C/C distance between columns = 8m; Self-weight of rail section = 300 N/m; Yield stress = 250 N/mm². Design the main gantry section. Connection design not required.

15 marks

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6

Design a laced column for an axial load of 1200 kN with an effective span of 7.5m has one end fixed and other end hinged. Use channels for main members and an angle 45° for lacing bars. Sketch the details of the section.

15 marks

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715 marks
a

Explain the concept of plastic hinge.

7 marks

Answer

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b

Find the collapse load for the three-span continuous beam. The plastic moment capacity of the end-span sections is two-third of the plastic moment capacity (Mp) of the mid-span section.

8 marks

Answer

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8

Design an I section purlin for an industrial building, located at Chennai, with Galvanised iron sheets as the roofing material. Span of the truss = 13m; Spacing of trusses = 6m c/c; Spacing of purlins = 1.2m c/c; Wind pressure intensity = 2 kN/m²; Weight of GI sheets = 130 N/m²; Grade of Steel: Fe 410.

15 marks

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About this paper

This page contains the solved question paper with answers of STRUCTURAL ENGINEERING - II (STEEL) from Jawaharlal Nehru Technological University Hyderabad for B.Tech CE III Year II Semester, August - 2022, R18.

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