Jawaharlal Nehru Technological University Hyderabad
Jawaharlal Nehru Technological University Hyderabad B.Tech IV ESTIMATING AND COSTING Previous Question Paper (September - 2020 - R16)
Answer any five questions. All questions carry equal marks.
Main
The details of a residential building are shown in figure 1. Work out the quantities of the following items of work by centre line method. Calculate the centre line and No. of Junction. SSM in CM 1:8 for foundation.
Answer
The centre line method is an efficient technique for estimating quantities where the total length of the centre line of walls is calculated first. For a building with a main room and attached walls, the total centre line length is determined by summing the lengths of all wall centrelines, ensuring that corners are not double-counted.
To calculate the total centre line length, use the formula: L = Σ(centre-to-centre length of walls). For each junction where two walls meet, deduct half the width of the wall from the total length to avoid overlapping volumes. The number of junctions is defined as the number of points where a wall meets another wall at a T-junction or L-junction.
For SSM (Selected Stone Masonry) in CM 1:8 for foundation, the quantity is calculated as follows:
- Determine the total centre line length (L) of the foundation trenches by measuring from the centre of the wall sections.
- Identify the number of junctions (n) and calculate the deduction: Total Length = L - (n × width of foundation / 2).
- Calculate the quantity: Quantity = (Total Length) × (Width of foundation) × (Depth of foundation).
The specific quantity for SSM in foundation is derived by multiplying the net centre line length by the cross-sectional area of the foundation trench (width × depth). Ensure that the width used corresponds to the foundation base width, not the superstructure wall width.
The details of a residential building are shown in figure 1. Work out the quantities of the following items of work by centre line method. Earthwork Excavation for all foundation.
Answer
The centre line method involves calculating the total length of the centre line of the foundation trenches for all walls (main and partition) and multiplying this length by the cross-sectional area of the excavation to determine the total quantity.
The calculation steps are as follows:
- Calculate the total centre line length: Sum the lengths of all centre lines of the foundation trenches. For junctions, subtract half the width of the foundation for every junction where two or more walls meet to avoid double counting.
- Determine the cross-sectional area of excavation: Identify the width and depth of the foundation trench as per the provided drawing. The area is calculated as: Area = Width of foundation × Depth of excavation
- Calculate the total quantity: Multiply the total centre line length by the cross-sectional area: Total Quantity = Total Centre Line Length × Width of foundation × Depth of excavation
Note: Since specific dimensions from 'Figure 1' were not provided in the text, the final numerical value depends on the specific lengths, widths, and depths indicated in the diagram. Ensure that all deductions for junctions are performed systematically to maintain accuracy.
Following table gives RL for a portion of 400m length of road width=10m, side slope (2:1) in filling and (1.5:1) in cutting (H:V). Compute the quantity of earthwork.
| Distance(m) | 0 | 40 | 80 | 120 | 160 | 200 | 240 | 280 | 320 | 360 | 400 |
|---|---|---|---|---|---|---|---|---|---|---|---|
| RL of ground(m) | 31 | 30.9 | 30.5 | 30.8 | 30.6 | 30.7 | 31.2 | 31.4 | 31.3 | 31 | 30.6 |
RL of formation(m): 32, Down gradient 1 in 100.
Answer
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Estimate the quantity and cost of earthwork for a portion of a road from the following data using Mid-sectional area (Mean depth) method.
| Distance(m) | 0 | 40 | 80 | 120 | 160 | 200 | 240 | 280 | 320 | 360 | 400 |
|---|---|---|---|---|---|---|---|---|---|---|---|
| RL of Ground | 51.0 | 50.9 | 50.5 | 50.8 | 50.6 | 50.7 | 51.2 | 51.4 | 51.3 | 51.0 | 50.6 |
RL of Formation: 52.00, downward gradient 1 in 200.
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Workout from the first principles, the rate per unit of the following:
First class brickwork in CM 1:6 in superstructure.
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Plastering of brick walls 12 mm thick with 1:4 CM.
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Work out from the first principles the rate per unit of the following:
Cement concrete bed for foundation 1:4:8.
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12mm thick Cement mortar 1:3 plastering for ceiling.
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Define contract. Explain different types of contract.
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Write detailed specifications for the following:
Cement plastering in CM 1:4.
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RCC 1:2:4 for roof slab.
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