Jawaharlal Nehru Technological University Hyderabad

Jawaharlal Nehru Technological University Hyderabad B.Tech I Year MATHEMATICS - II Previous Question Paper (June - 2022 - R16)

B.Tech | I Year | II Semester | R16 | June - 2022

Answer PaperPaper Code: 132ABMaximum Marks: 75Time: 3 Hours

Answer any five questions. All questions carry equal marks.

Main

115 marks
a

Find L-1{ (s+5)/(s2+2s+5) + (1+s)/(s2+3s+6) + 4/(s-2)3 + 5/(s+3)6 }.

9 marks

Answer

To find the inverse Laplace transform of the given function, we use the method of partial fraction decomposition. Let the function be:

F(s) = (s² + 5s + 3) / ((s-4)(s² + 2s + 5))

We express F(s) as:

F(s) = A / (s-4) + (Bs + C) / (s² + 2s + 5)

Equating the numerators:

s² + 5s + 3 = A(s² + 2s + 5) + (Bs + C)(s-4)

Setting s = 4:

16 + 20 + 3 = A(16 + 8 + 5) => 39 = 29A => A = 39/29

Comparing coefficients of s²:

1 = A + B => B = 1 - 39/29 = -10/29

Comparing constants:

3 = 5A - 4C => 3 = 5(39/29) - 4C => 4C = 195/29 - 87/29 = 108/29 => C = 27/29

Substituting back:

F(s) = (39/29)/(s-4) + (-10/29s + 27/29) / ((s+1)² + 2²)

Rewriting the second term to match standard forms:

(-10/29)(s+1-1) + 27/29 = (-10/29)(s+1) + 37/29

Applying the inverse Laplace transform:

f(t) = (39/29)e⁴ᵗ - (10/29)e⁻ᵗcos(2t) + (37/58)e⁻ᵗsin(2t)
b

Find L-1{ 1/(s(s-1)) }.

6 marks

Answer

To find the inverse Laplace transform of 1/(s(s-1)), we use partial fraction decomposition:

1 / (s(s-1)) = A/s + B/(s-1)

Equating numerators:

1 = A(s-1) + Bs

Setting s = 0 gives A = -1. Setting s = 1 gives B = 1. Thus:

1 / (s(s-1)) = 1/(s-1) - 1/s

Taking the inverse Laplace transform:

L⁻¹{1/(s-1)} - L⁻¹{1/s} = eᵗ - 1
215 marks
a

Use Laplace transform to prove that ∫0∞ (sin t)/t dt = π/4.

7 marks

Answer

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b

Find the inverse Laplace transform of e-πs/(s2+1).

8 marks

Answer

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315 marks
a

Show that ∫01 xm-1(1-x)n-1 dx = β(m, n).

9 marks

Answer

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b

Evaluate ∫ sin5 x dx and hence find ∫0π/2 sin5 x dx.

6 marks

Answer

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415 marks
a

Change the order of integration and solve ∫0a ∫x2/a√(2ax-x2) xy dy dx.

7 marks

Answer

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b

Evaluate ∫∫ dx dy / (x4+y4), over the region bounded by x ≥ y ≥ 1.

8 marks

Answer

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515 marks
a

Prove that ∇(f/g) = 1/g2 (g ∇f - f ∇g).

6 marks

Answer

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b

Given the velocity potential f of a flow, find the velocity field ∇f = v and its value v(P) at P where f = cos x cosh y, P: (π/2, ln 2).

9 marks

Answer

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615 marks
a

Prove that ∇(fn) = nfn-1∇f.

7 marks

Answer

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b

For what points P(x, y, z) does ∇f with f = 25x2 + 9y2 + 16z2 have the direction from P to the origin?

8 marks

Answer

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7

Evaluate ∫C F ⋅ dr around the boundary C of the region R by Green’s Theorem, where F = grad(x3 cos2(xy)) and R: 1 ≤ y ≤ 2 - x2.

15 marks

Answer

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8

Evaluate ∮C ez dx + 2y dy - dz by Stoke’s theorem when c is the curve x2 + y2 = 4, z = 2.

15 marks

Answer

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About this paper

This page contains the question paper of MATHEMATICS - II from Jawaharlal Nehru Technological University Hyderabad for B.Tech CSBS I Year II Semester, June - 2022, R16.

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