JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech II NETWORK ANALYSIS AND TRANSMISSION LINES Previous Question Paper (October - 2020 - R18)

B.Tech | II | I | R18 | October - 2020

Answer PaperPaper Code: 153BHMaximum Marks: 75Time: 2 hours

Answer any five questions. All questions carry equal marks.

Main

115 marks
a

Derive an expression for coefficient of coupling between two mutually coupled coils.

7 marks

Answer

Consider two coils with self-inductances L1 and L2 placed in proximity such that they are magnetically coupled. Let M be the mutual inductance between them. The flux produced by coil 1 is divided into two parts: the leakage flux (Φl1) and the useful flux that links coil 2 (Φm1). Similarly, for coil 2, the flux is divided into leakage flux (Φl2) and the flux linking coil 1 (Φm2).

The self-inductances are defined as:

L1 = N1Φ1 / I1
L2 = N2Φ2 / I2

The mutual inductance is defined by the flux linkage of one coil due to current in the other:

M = N2Φm1 / I1 = N1Φm2 / I2

Multiplying the two expressions for M:

M2 = (N1N2Φm1Φm2) / (I1I2)

Since Φm1 = k1Φ1 and Φm2 = k2Φ2, where k1 and k2 are the fractions of flux linking the other coil:

M2 = k1k2 (N1Φ1 / I1) (N2Φ2 / I2) = k1k2 L1L2

Defining the coefficient of coupling as K = √(k1k2), we obtain:

M = K√(L1L2)
b

The number of turns in two coupled coils is 250 and 750 respectively. When 2.5 A current flows in coil 1, the total flux in this coil is 0.3 milli Wb and the flux linking the second coil is 0.15 Wb. Determine L1, L2, M and K.

8 marks

Answer

Given: N1 = 250, N2 = 750, I1 = 2.5 A, Φ1 = 0.3 mWb = 0.3 × 10-3 Wb, Φm1 = 0.15 mWb = 0.15 × 10-3 Wb.

  • L1 Calculation:
    L1 = (N1 × Φ1) / I1 = (250 × 0.3 × 10-3) / 2.5 = 0.03 H = 30 mH
  • M Calculation:
    M = (N2 × Φm1) / I1 = (750 × 0.15 × 10-3) / 2.5 = 0.045 H = 45 mH
  • K Calculation:
    K = Φm1 / Φ1 = 0.15 / 0.3 = 0.5
  • L2 Calculation: Using M = K√(L1L2):
    L2 = M2 / (K2 × L1) = (0.045)2 / (0.52 × 0.03) = 0.27 H = 270 mH
215 marks
a

Explain the following: (i) sub graph (ii) connected graph and (iii) Planar graph.

6 marks

Answer

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b

Obtain the fundamental circuit matrix for the graph in the figure 1. Choose the tree consisting of branches 6, 7, 8 and 9.

9 marks

Answer

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3

Obtain the response of the current flowing through a Series RLC circuit when excited by a step voltage by closing the switch at t = 0+.

15 marks

Answer

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415 marks
a

The circuit in figure 2 is operating under steady state condition when the switch is at position ‘a’ and at t = 0, the switch is moved to position ‘b’. Determine the current i(t).

8 marks

Answer

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b

An inductance of 0.6 H, a resistance of 6 ohm and a capacitance of 10 μF are in series across a 230 V, A.C supply. Calculate the frequency at which the circuit resonates. Find the current at resonance, bandwidth, half power frequencies and the voltage across capacitance at resonance.

7 marks

Answer

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5

Determine the driving point impedance V1/I1, transfer impedance V2/I1 and voltage transfer ratio V2/V1 for the network shown in Figure 3.

15 marks

Answer

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6

The z-parameters of a certain two port network are Z11 = 5 Ω, Z12 = Z21 = 3 Ω and Z22 = 4 Ω. Determine its y-parameters, transmission parameters, and hybrid parameters (h) and inverse hybrid parameters (g).

15 marks

Answer

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715 marks
a

Calculate the characteristic impedance for the following line parameters: R = 10.4 ohms/km; L = 0.00367 H/km; C = 0.00835 μF/km and G = 10.8×10-6 mhos/km.

8 marks

Answer

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b

State the properties of infinite line.

7 marks

Answer

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8

Derive an expression for the input impedance of distortion less lines. Deduce the input impedance of open and short circuited distortion less lines.

15 marks

Answer

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This page contains the solved question paper with answers of NETWORK ANALYSIS AND TRANSMISSION LINES from JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD for B.Tech ECE II I, October - 2020, R18.

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