JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech II ANALOG COMMUNICATIONS Previous Question Paper (August/September - 2022 - R16)

B.Tech | II | II | R16 | August/September - 2022

Answer PaperPaper Code: 134ACMaximum Marks: 75Time: 3 Hours

Answer any five questions. All questions carry equal marks.

Main

115 marks
a

Explain the concept of Frequency Division Multiplexing with neat block diagram.

5 marks

Answer

Frequency Division Multiplexing (FDM) is a technique where the available bandwidth of a communication channel is divided into several non-overlapping frequency slots. Each slot is assigned to a different signal, allowing multiple signals to be transmitted simultaneously over a single physical medium.

The process involves modulating each baseband signal onto a distinct carrier frequency. These modulated signals are then combined using a summer circuit and transmitted. At the receiver, bandpass filters are used to separate the signals, followed by individual demodulators to recover the original baseband information.

Block Diagram Description: The transmitter consists of multiple signal sources (m1, m2, ..., mn) connected to individual modulators (MOD1, MOD2, ..., MODn) driven by different carrier frequencies (f1, f2, ..., fn). The outputs are combined in a summer and sent through a channel. The receiver uses a bank of bandpass filters (BPF1, BPF2, ..., BPFn) tuned to the respective carrier frequencies to extract the signals, which are then passed through demodulators to retrieve the original messages.

b

Explain the principle of operation of Envelope Detector used for AM detection, with necessary equations.

10 marks

Answer

An envelope detector is a simple and efficient circuit used to recover the message signal from an Amplitude Modulated (AM) wave. It consists of a diode, a resistor, and a capacitor connected in parallel.

Operation Principle: When the AM signal is applied to the diode, it acts as a half-wave rectifier, allowing only the positive half-cycles to pass. The capacitor charges rapidly to the peak value of the input signal through the low forward resistance of the diode. When the input voltage falls below the capacitor voltage, the diode becomes reverse-biased and stops conducting. The capacitor then discharges slowly through the resistor R. If the time constant (RC) is chosen correctly, the discharge rate follows the envelope of the AM signal.

Mathematical Representation: An AM signal is given by:

s(t) = A[1 + kam(t)]cos(2πfct)

Where A is the carrier amplitude, ka is the sensitivity, and m(t) is the message signal. The envelope detector extracts the envelope:

E(t) = A[1 + kam(t)]

To ensure accurate detection, the RC time constant must satisfy the condition:

1/fc << RC << 1/W

where fc is the carrier frequency and W is the highest frequency component of the message signal. This ensures the capacitor tracks the carrier peaks without following the rapid carrier oscillations, while also being able to discharge fast enough to follow the variations of the message signal.

215 marks
a

For an AM DSBFC modulator with a carrier frequency fc = 100 KHz and maximum modulating signal frequency fm = 10 KHz. Determine:

i) Frequency limits for upper and lower side bands

ii) Bandwidth

iii) Draw the Output frequency spectrum

iv) Modulation index for a carrier signal amplitude of 20 V and message signal amplitude of 5V.

10 marks

Answer

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b

With necessary circuit diagram and waveforms, explain how DSBSC wave is generated using Ring modulator.

5 marks

Answer

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315 marks
a

Illustrate the block diagram for the generation of SSB-SC using Phase discrimination method.

8 marks

Answer

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b

Explain the Hilbert transform with suitable equations.

7 marks

Answer

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415 marks
a

Describe the VSB modulation in time domain frequency domain.

7 marks

Answer

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b

Explain in detail about the Demodulation of SSB Waves.

8 marks

Answer

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515 marks
a

Derive an expression for Wide Band Frequency Modulation.

10 marks

Answer

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b

Determine the peak frequency deviation and modulation index for FM modulator Deviation sensitivity 5KHz/V and modulating signal 3 cos (2π1000t).

5 marks

Answer

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615 marks
a

Draw the diagram of Balanced Frequency discriminator and explain its operation.

10 marks

Answer

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b

An FM wave is given by e(t)=20cos(8π×106t+9sin(2π×103t)). Calculate the bandwidth, and power of FM wave.

5 marks

Answer

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715 marks
a

Explain the Noise Performance of Angle Modulation System.

10 marks

Answer

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b

Write Short notes on Narrow band Noise.

5 marks

Answer

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815 marks
a

Explain in detail FM super heterodyne receiver with neat block diagram.

10 marks

Answer

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b

Explain the generation of PPM signal.

5 marks

Answer

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About this paper

This page contains the question paper of ANALOG COMMUNICATIONS from JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD for B.Tech ECE II II, August/September - 2022, R16.

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