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JNTU B.Tech III DIGITAL COMMUNICATIONS Previous Question Paper (September 2021 - R16)

B.Tech | III | I | R16 | September 2021

Answer PaperPaper Code: 135AKMaximum Marks: 75Time: 3 Hours

Answer any five questions. All questions carry equal marks.

Main

115 marks
a

Explain a DPCM system. Derive the expression for slope overload noise.

8 marks

Answer

Differential Pulse Code Modulation (DPCM) is a technique where the difference between the current sample value and its predicted value is quantized and transmitted. The system consists of a predictor and a quantizer. The predictor estimates the current sample based on previous samples, and the error signal (difference between actual and predicted value) is quantized to reduce redundancy.

Slope overload noise occurs in predictive systems when the input signal changes faster than the system can track. If the input signal x(t) has a maximum slope of x'(t) and the system step size is Δ with sampling period T_s, the condition for no slope overload is:

|dx(t)/dt| ≤ Δ / T_s

If the input signal exceeds this rate, the predictor cannot keep up, leading to a tracking error that grows linearly. The slope overload noise power is proportional to the square of the difference between the signal slope and the maximum tracking slope of the system.

b

Explain the process of quantization and obtain the expression for signal to quantization ratio in the case of uniform quantizer?

7 marks

Answer

Quantization is the process of mapping a continuous amplitude signal into a finite set of discrete levels. For a uniform quantizer with a total range of V volts and L levels, the step size is Δ = V / L. Assuming the quantization error e is uniformly distributed between -Δ/2 and +Δ/2, the mean square quantization noise power N_q is:

N_q = E[e^2] = 1/Δ ∫-Δ/2Δ/2 e^2 de = Δ^2 / 12

If the signal power is S, the Signal-to-Quantization Noise Ratio (SQNR) is given by:

SQNR = S / N_q = 12S / Δ^2

For a sinusoidal signal with amplitude A, S = A^2 / 2. Substituting Δ = 2A / L, the SQNR becomes:

SQNR = 12(A^2 / 2) / (4A^2 / L^2) = 1.5 L^2

In decibels, this is expressed as SQNR(dB) = 1.76 + 6.02n, where n is the number of bits per sample (L = 2^n).

215 marks
a

Describe the steps involved in generation of linear block codes.

7 marks

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b

Determine the generator polynomial g(x) for a (7, 4) cyclic code and find code vectors for the following data vectors 1010, 1111 and 1000.

8 marks

Answer

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315 marks
a

Explain the Shannon-Fano coding with an example.

8 marks

Answer

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b

Explain the measure of information and its properties.

7 marks

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415 marks
a

Discuss about M array PAM transmission.

6 marks

Answer

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b

Explain correlation receiver with neat block diagram.

9 marks

Answer

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515 marks
a

Explain the signal space representation of a QPSK.

7 marks

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b

Explain the transmitter, receiver of BPSK.

8 marks

Answer

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615 marks
a

Discuss about pass band transmission model with example.

8 marks

Answer

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b

Explain about adaptive equalization.

7 marks

Answer

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715 marks
a

Explain Generating Pseudo-Random codes, code correlation and Pseudo Noise spreading.

10 marks

Answer

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b

How is synchronization achieved in DSSS?

5 marks

Answer

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815 marks
a

With necessary diagram explain the frequency hopping spread spectrum.

8 marks

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b

Derive Processing gain for spread spectrum system.

7 marks

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This page contains the question paper of DIGITAL COMMUNICATIONS from JNTU for B.Tech ECE III I, September 2021, R16.

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