JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech III ELECTRONIC CIRCUIT ANALYSIS Previous Question Paper (July - 2021 - R18)

B.Tech | III | I | R18 | July - 2021

Answer PaperPaper Code: 155SFMaximum Marks: 75Time: 3 Hours

Answer any five questions

All questions carry equal marks

Main

115 marks
a

Discuss about the different amplifier configurations and compare their characteristics with performance applications.

5 marks

Answer

The three basic BJT amplifier configurations are Common Emitter (CE), Common Collector (CC), and Common Base (CB).

  • Common Emitter (CE): The emitter is common to both input and output. It provides high voltage gain, high current gain, and high power gain. It is widely used in general-purpose amplification and audio frequency applications.
  • Common Collector (CC): The collector is common to both input and output. It provides high input impedance and low output impedance with a voltage gain of approximately unity. It is primarily used as a buffer or impedance matching stage.
  • Common Base (CB): The base is common to both input and output. It provides low input impedance and high output impedance with a current gain less than unity. It is typically used in high-frequency applications due to its excellent stability.
b

Consider a single stage CE amplifier with RS = 1K, R1 = 50 K, R2 = 2 K, RC = 1K, RL = 1.2K, hfe = 50, hie = 1.1K, hre = hoe = 0; Find AI, Ri, Ro, AV and power gain.

10 marks

Answer

Given parameters: RS = 1KΩ, R1 = 50KΩ, R2 = 2KΩ, RC = 1KΩ, RL = 1.2KΩ, hfe = 50, hie = 1.1KΩ, hre = 0, hoe = 0.

  1. Input Resistance (Ri): The base bias resistors R1 and R2 are in parallel. RB = (R1 || R2) = (50K || 2K) ≈ 1.923KΩ. The input resistance looking into the base is hie = 1.1KΩ. Thus, Ri = RB || hie = (1.923K || 1.1K) ≈ 0.7KΩ.
  2. Current Gain (AI): The load resistance RL' = RC || RL = (1K || 1.2K) ≈ 0.545KΩ. AI = -hfe * (RC / (RC + RL)) = -50 * (1 / 2.2) ≈ -22.73.
  3. Voltage Gain (AV): AV = (AI * RL') / Ri = (-22.73 * 0.545K) / 0.7K ≈ -17.69.
  4. Output Resistance (Ro): Since hoe = 0, the output resistance looking into the collector is Ro = RC = 1KΩ.
  5. Power Gain (AP): AP = |AV * AI| = |-17.69 * -22.73| ≈ 402.08.
215 marks
a

Discuss about different types of distortions that occur in amplifier circuits.

6 marks

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b

Differentiate the operational difference between direct coupled amplifier, RC coupled amplifier and transformer coupled amplifier.

9 marks

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3

Discuss the classifications of different feedback amplifiers and derive the expressions for voltage gain and output resistance and input resistance current series feedback.

15 marks

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415 marks
a

Derive the expression for frequency of Oscillation for a Colpitts Oscillator.

9 marks

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b

Given a Hartley Oscillator circuit L2=0.04mH, C=0.004μF. If the frequency of Oscillation is 150kHz, find L1 by neglecting the mutual Inductance parameter.

6 marks

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515 marks
a

Explain the operation of Class-B power amplifier and write how to eliminate cross over distortions in the application of these amplifiers.

8 marks

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b

Explain the importance of the position of operating point on output signal swing in Class -A power amplifier and prove that the conversion efficiency is 25%.

7 marks

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6

Differentiate between the stagger tuned and synchronous tuned amplifiers with their frequency responses and derive the overall gain functions of these amplifiers.

15 marks

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715 marks
a

Explain the principle of operations of bi-stable and a-stable multi-vibrators.

8 marks

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b

Write about the Schmitt trigger and its wave forms for signal generation.

7 marks

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815 marks
a

Explain the concepts of Transistor Miller and Bootstrap Time Base Generator design.

10 marks

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b

Discuss the effects of Feedback on Amplifier characteristics.

5 marks

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