JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech III ELECTRICAL MACHINE DESIGN Previous Question Paper (September - 2021 - R18)

B.Tech | III | I | R18 | September - 2021

Answer PaperPaper Code: 155BBMaximum Marks: 75Time: 3 hours

Answer any five questions. All questions carry equal marks.

Main

115 marks
a

Briefly discuss the factors those limit the design of the machine.

8 marks

Answer

The design of an electrical machine is constrained by several physical, thermal, and economic factors that dictate the limits of its performance:

  • Thermal Loading: The insulation system is the primary limiting factor. Heat generated by copper and iron losses must be dissipated to prevent insulation degradation. The maximum allowable temperature rise defines the machine's rating.
  • Magnetic Loading: This is limited by the magnetic saturation of the core material (typically silicon steel). Excessive flux density leads to high iron losses and high magnetizing current, reducing efficiency.
  • Electric Loading: Limited by the current density in the conductors and the available space for insulation. High current density leads to excessive I²R losses and heating.
  • Speed and Mechanical Stress: High rotational speeds introduce centrifugal forces that impose mechanical stress on the rotor, requiring robust construction and careful balancing.
  • Voltage Regulation and Power Factor: The leakage reactance of the windings limits the machine's ability to maintain stable voltage under load and affects the overall power factor.
  • Economic Factors: The cost of active materials (copper and steel) versus the efficiency and performance requirements dictates the optimal design point.
b

What are the merits and demerits due to higher electric loading?

7 marks

Answer

Higher electric loading (defined as the number of armature conductors per unit of armature periphery) significantly influences machine characteristics:

Merits:

  • Reduction in the overall size and weight of the machine for a given power output, leading to lower material costs.
  • Improved material utilization, as more copper is packed into the slots.
  • Higher power density, which is advantageous for space-constrained applications.

Demerits:

  • Increased copper losses (I²R), which leads to lower efficiency and higher operating temperatures.
  • Requirement for more sophisticated cooling systems to handle the increased heat dissipation.
  • Higher leakage reactance, which negatively impacts voltage regulation and may lead to commutation difficulties in DC machines.
  • Increased risk of insulation failure due to higher thermal stress.
215 marks
a

What are the electrical materials used in machines? Discuss them.

9 marks

Answer

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b

Explain the selection of motor power ratings.

6 marks

Answer

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315 marks
a

Optimize the transformer design from the point of view of (i) minimum cost and (ii) minimum loss.

8 marks

Answer

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b

What is window space factor? Find the width of window for optimum output of a transformer.

7 marks

Answer

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4

Determine the main dimensions of the core, the number of turns and cross section of the conductors for a 5 kVA, 11000/400 V, 50 Hz, single phase core type distribution transformer. The net conductor area in the window is 0.6 times the net cross section of iron in the core. Assume a square cross section for the core, a flux density 1 Wb/m2, a current density 1.4 A/mm2 and a window space factor 0.2. The height of window is 3 times its width.

15 marks

Answer

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515 marks
a

Which factor should be considered when estimating the length of the air gap of induction motor? Why the airgaps should be as small as possible?

8 marks

Answer

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b

Comment on shape and sizes of rotor bars in induction motor.

7 marks

Answer

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6

Determine the main dimensions, turns per phase, number of slots, conductor cross section and slot area of a 250 HP, 3-phase, 50 Hz, 1410 r.p.m slip ring induction motor. Assume Bav = 0.5 Wb/m2, exciting current (ac) = 30000 A/m, efficiency = 0.9 and power factor = 0.9, winding factor = 0.955, current density = 3.5 A/mm2. The slot space factor is 0.4 and the ratio of core length to pole pitch is 1.2. The machine is delta connected.

15 marks

Answer

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715 marks
a

What are the factors to be considered to select the specific electrical loading of synchronous generator.

8 marks

Answer

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b

How would you calculate the full load field mmf in a synchronous machine?

7 marks

Answer

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8

Illustrate the finite element-based method of design of permanent magnetic synchronous motors.

15 marks

Answer

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This page contains the solved question paper with answers of ELECTRICAL MACHINE DESIGN from JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD for B.Tech EEE III I, September - 2021, R18.

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