JNTU

JNTU B.Tech III MEASUREMENTS AND INSTRUMENTATION Previous Question Paper (February - 2022 - R18)

B.Tech | III | III-I | R18 | February - 2022

Answer PaperPaper Code: 155CBMaximum Marks: 75Time: 3 hours

Answer any five questions

All questions carry equal marks

Main

115 marks
a

A moving coil instrument gives a full-scale deflection of 10mA when the potential difference across its terminal is 100mV. Calculate,

i) The shunt resistance for a full-scale deflection of 100A

ii) Find the resistance for full-scale reading with 100V

Also, calculate the power dissipation in each case.

8 marks

Answer

First, determine the internal resistance of the instrument (Rm):

Rm = Vm / Im = 100 mV / 10 mA = 10 Ω

i) For a shunt resistance (Rsh) to measure 100 A:

Rsh = (Im * Rm) / (I - Im) = (0.01 * 10) / (100 - 0.01) ≈ 0.0010001 Ω

Power dissipation in the shunt: Psh = Ish2 * Rsh ≈ (99.99)2 * 0.0010001 ≈ 10 W.

ii) For a series resistance (Rse) to measure 100 V:

Rse = (V / Im) - Rm = (100 / 0.01) - 10 = 9990 Ω

Power dissipation in the series resistor: Pse = Im2 * Rse = (0.01)2 * 9990 = 0.999 W.

b

Derive an equation for the torque developed in PMMC instrument.

7 marks

Answer

In a PMMC instrument, the deflecting torque (Td) is produced by the interaction of the magnetic field and the current-carrying coil. The force on one side of the coil is F = BIlN, where B is flux density, I is current, l is length of the conductor, and N is the number of turns. For two sides of the coil, the torque is:

Td = F * d = (B * I * l * N) * d

Since the area of the coil A = l * d, the equation becomes:

Td = B * A * N * I

Where:

  • B = Flux density in the air gap (Wb/m2)
  • A = Area of the coil (m2)
  • N = Number of turns
  • I = Current in the coil (A)

Thus, Td = G * I, where G = BAN is the displacement constant, showing that the deflecting torque is directly proportional to the current.

215 marks
a

A PMMC ammeter has following specification, coil dimension of 1cm×1cm, spring constant is 0.15×10-6 N-m/rad, Flux density is 1.5×10-3wb/m2. Determine the number of turns required to produce a deflection of 90°, when a current of 2mA flows through the coil.

7 marks

Answer

Sign in to view the complete answer paper.

b

With the help of a neat diagram, explain the working of attracted disc type voltmeter.

8 marks

Answer

Sign in to view the complete answer paper.

315 marks
a

Discuss how AC potentiometer can be used for calibration of wattmeter.

8 marks

Answer

Sign in to view the complete answer paper.

b

Explain the procedure to calibrate voltmeter and ammeter using DC potentiometer.

7 marks

Answer

Sign in to view the complete answer paper.

415 marks
a

With help of a neat diagram explain the working of coordinate type potentiometer.

8 marks

Answer

Sign in to view the complete answer paper.

b

Draw the equivalent circuit diagram and phasor diagram of the current transformer.

7 marks

Answer

Sign in to view the complete answer paper.

515 marks
a

Discuss the construction and Working Principle of Electrodynamometer type 1-φ wattmeter with help of a neat diagram.

9 marks

Answer

Sign in to view the complete answer paper.

b

Explain any two errors that occur in electrodynamometer type 1-φ wattmeter and its compensation.

6 marks

Answer

Sign in to view the complete answer paper.

615 marks
a

With help of a neat diagram, explain the construction and working of a three-phase energy meter.

9 marks

Answer

Sign in to view the complete answer paper.

b

Two-watt meters are connected to measure the input to a balanced 3 phase circuit indicating 2000W and 500W respectively. Find the power factor of a circuit,

i) When both the reading is positive and

ii) When the latter reading is obtained after reversing the connections to the current coil of the first instrument.

6 marks

Answer

Sign in to view the complete answer paper.

715 marks
a

Draw the circuit of Kelvin double bridge used for measurement of low resistance. Explain its working principle

8 marks

Answer

Sign in to view the complete answer paper.

b

An AC bridge is balanced at 2KHz with the following components in each arm: Arm AB=10KΩ, Arm BC=100µF in series with 100KΩ, Arm AD=50KΩ. Find the unknown impendence R ± jX in the arm DC, if the detector is between BD.

7 marks

Answer

Sign in to view the complete answer paper.

815 marks
a

Derive an equation for gauge factor in strain gauge.

7 marks

Answer

Sign in to view the complete answer paper.

b

With help of a neat diagram, explain the principle and working of LVDT.

8 marks

Answer

Sign in to view the complete answer paper.

About this paper

This page contains the solved question paper with answers of MEASUREMENTS AND INSTRUMENTATION from JNTU for B.Tech EEE III III-I, February - 2022, R18.

For the question paper without answers, switch to the Question Paper tab.

Other papers in MEASUREMENTS AND INSTRUMENTATION

Loading Question Papers

Fetching data from database...