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JNTU B.Tech III SIGNAL CONDITIONING CIRCUITS Previous Question Paper (March - 2021 - R13)

B.Tech | III | I | R13 | March - 2021

Answer PaperPaper Code: 115AXMaximum Marks: 75Time: 3 hours

Answer any five questions. All questions carry equal marks.

Main

115 marks
a

What is ground and ground loops? Describe the methods for reducing interference in instrumentation with neat diagrams.

8 marks

Answer

Ground is a common reference point in an electrical circuit, ideally at zero potential, providing a return path for current. A ground loop occurs when two or more points in a circuit are connected to ground at different physical locations, creating a potential difference between them. This causes circulating currents to flow through the ground conductor, inducing noise and interference in sensitive instrumentation signals.

Methods to reduce interference include:

  • Single-Point Grounding: Connecting all signal grounds to a single physical point to prevent circulating currents.
  • Differential Signaling: Using balanced transmission lines to reject common-mode noise.
  • Shielding and Isolation: Employing Faraday shields or galvanic isolation (e.g., opto-isolators or transformers) to break the conductive path of the ground loop.
  • Cable Routing: Keeping signal cables away from high-power lines and using twisted-pair wiring to cancel electromagnetic interference.
b

A 350 Ω strain gauge having G = 2.1 is attached to an aluminum strut (E=73 GPa). The outside diameter is 47.5 mm. Calculate the change in the resistance when the strut supports a 1000 kg load.

7 marks

Answer

Given: Resistance R = 350 Ω, Gauge factor G = 2.1, Young's modulus E = 73 GPa = 73 × 109 N/m2, Load F = 1000 kg × 9.81 m/s2 = 9810 N, Diameter d = 47.5 mm = 0.0475 m.

First, calculate the cross-sectional area A of the strut:

A = π × (d/2)2 = π × (0.02375)2 ≈ 1.772 × 10-3 m2

Next, calculate the stress (σ) and strain (ε):

σ = F / A = 9810 / 1.772 × 10-3 ≈ 5.536 × 106 Pa
ε = σ / E = (5.536 × 106) / (73 × 109) ≈ 7.584 × 10-5

Finally, calculate the change in resistance (ΔR):

ΔR = R × G × ε = 350 × 2.1 × 7.584 × 10-5 ≈ 0.0557 Ω
215 marks
a

Explain the operation of wheat stone bridge when the resistors are in series and parallel. How wheat stone bridge uses in light detector.

8 marks

Answer

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b

Why use a three op-amp instrumentation amplifier? Draw and explain the practical instrumentation amplifier.

7 marks

Answer

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315 marks
a

Sketch and explain simplified resolver to digital converter architecture.

7 marks

Answer

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b

Justify, why the Circuits often require an integrated AC power source as the optimum strategy to reduce size.

8 marks

Answer

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415 marks
a

Suggest a design to reduce the noise and increase the bandwidth in carrier amplifiers in analog devices.

7 marks

Answer

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b

List the limitations of analog signal conditioning approach and propose an alternative design methodology using digital signal processors.

8 marks

Answer

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515 marks
a

Why coupling capacitor should be very large in chopper amplifiers and draw the relevant plots between V and T when both switches are closed and open.

8 marks

Answer

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b

Specify an example for leakage current measurement repeatability and design a circuit for measurement of integration time for leakage currents.

7 marks

Answer

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615 marks
a

Differentiate electrometer and nonvoltmeter characteristics in terms of input offset current and impedance.

7 marks

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b

What is a resistor noise? Name and describe various noise standards in terms of low noise resistor.

8 marks

Answer

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715 marks
a

Draw and explain the block diagram of digital tachometer to measure velocity of a motor shaft.

8 marks

Answer

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b

What is an ARCNET bus and specify the features based on three different applications.

7 marks

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815 marks
a

List the electrical characteristics of ultrasonic sensors and describe the construction and operation principle of open structure type.

8 marks

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b

Justify MOSFET as a switch and discuss the impact of MOSFET based sensors in manufacturing industry.

7 marks

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