Jawaharlal Nehru Technological University Hyderabad

Jawaharlal Nehru Technological University Hyderabad B.Tech IV Year MECHANICAL VIBRATIONS Previous Question Paper (September - 2022 - R18)

B.Tech | IV Year | II | R18 | September - 2022

Answer PaperPaper Code: 158BNMaximum Marks: 75Time: 3 Hours

Answer any five questions

All questions carry equal marks

Main

115 marks
a

What are the energy methods for vibration analysis? Discuss any one of it.

7 marks

Answer

Energy methods are analytical techniques used to determine the natural frequency of a vibrating system by equating the maximum kinetic energy to the maximum potential energy, based on the principle of conservation of energy. Common methods include the Rayleigh method, Rayleigh-Ritz method, and Dunkerley's method.

The Rayleigh Method is based on the principle that for a conservative system undergoing simple harmonic motion, the maximum kinetic energy (T_max) equals the maximum potential energy (V_max). For a system with a single degree of freedom, the natural frequency ω_n is given by:

ω_n = sqrt(V_max / T_max)

This method assumes a mode shape for the system. By calculating the kinetic energy of the masses and the potential energy of the elastic elements at the extreme position, the fundamental frequency can be estimated. It provides an upper bound to the fundamental frequency and is particularly useful for complex systems where exact solutions are difficult to derive.

b

An air craft instrument of mass 15 kg is to be isolated from the engine vibrations. The engine runs at speeds ranging from 1600 rpm to 2400 rpm. Determine the rubber stiffness for 95% isolation. Neglect damping?

8 marks

Answer

Given: Mass m = 15 kg, Frequency range = 1600 to 2400 rpm. Isolation efficiency η = 0.95 (95%).

First, convert the engine speed (f) to frequency in Hz:

f_min = 1600 / 60 = 26.67 Hz; f_max = 2400 / 60 = 40 Hz

The transmissibility (TR) is defined as 1 - η. For 95% isolation, TR = 1 - 0.95 = 0.05. The formula for transmissibility without damping is:

TR = | 1 / (r^2 - 1) | = 0.05

Where r = f / f_n. Since f > f_n, r^2 - 1 = 1 / 0.05 = 20, so r^2 = 21, and r = 4.58. To ensure 95% isolation across the entire range, we must design for the lowest excitation frequency (f_min = 26.67 Hz):

f_n = f_min / r = 26.67 / 4.58 = 5.82 Hz

The natural frequency in rad/s is ω_n = 2π * f_n = 2π * 5.82 = 36.57 rad/s. The stiffness k is calculated as:

k = m * (ω_n)^2 = 15 * (36.57)^2 = 20061 N/m

The required rubber stiffness is approximately 20.06 kN/m.

2

A disc of 5 kg mass is mounted in middle of simple supported horizontal shaft of span 0.5m and of diameter 10 mm. The centre of gravity of the disc is displaced 2.5 mm from geometric centre. The equivalent viscous damping for the system is 50 Ns/m, the shaft rotates at 740 rpm. Calculate a) dynamic stress in shaft b) static stress in shaft, c) power required to drive the shaft. Take E = 2 × 105 N/mm2.

15 marks

Answer

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3

A mass of 50 kg is supported by an elastic structure of total stiffness 20 kN/m. The damping ratio of the system is 0.2. A simple harmonic disturbing force acts on the mass and at any time t seconds, the force is 60cos(10t) Newton. Find the amplitude of the vibrations and the phase angle caused by the damping.

15 marks

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415 marks
a

Discuss briefly the advantages and disadvantages of the vibration oscillator.

7 marks

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b

Compare the frequency response of two reciprocating engine, one with a long connecting rod and the other with a short connecting rod, Assume the other parameters in the two engines are same.

8 marks

Answer

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515 marks
a

How do you determine the number of degrees of freedom system?

7 marks

Answer

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b

A mild steel shaft of 10 mm diameter is built into walls at both ends. It carries two flywheels, each at 0.25 m from a wall and also 0.25 m from each other, of steel 0.3 mm in diameter and 0.5 mm thick. Find the two natural frequencies in torsion.

8 marks

Answer

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6

For a taut string having tension T and three concentrated masses as shown in Figure below find the three natural frequencies.

15 marks

Answer

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715 marks
a

Explain the working of a accelerometer with a sketch?

7 marks

Answer

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b

A motor mass 10 kg is mounted on a shaft of stiffness 5000 N/m at the rotor. The equivalent damping coefficient of the system is 200 N-sec/m. When the shaft rotates at 500 rpm the power dissipated in damping is 8 Watts. Determine the eccentricity of rotor.

8 marks

Answer

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815 marks
a

Explain the relationship between sound power level and sound intensity.

8 marks

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b

Discuss the frequency dependent human response to sound.

7 marks

Answer

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This page contains the question paper of MECHANICAL VIBRATIONS from Jawaharlal Nehru Technological University Hyderabad for B.Tech ME IV Year II, September - 2022, R18.

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