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JNTU B.Tech IV Year HEAT TRANSFER Previous Question Paper (March - 2021 - R16)

B.Tech | IV Year | I Semester | R16 | March - 2021

Answer PaperPaper Code: 137DDMaximum Marks: 75Time: 3 Hours

Answer any Five Questions. All Questions Carry Equal Marks.

Main

115 marks
a

Describe different modes of heat transfer along with their basic laws and discuss different applications.

7 marks

Answer

Heat transfer occurs through three primary modes:

  1. Conduction: The transfer of energy through direct molecular interaction in solids or stationary fluids. It is governed by Fourier's Law of Heat Conduction: Q = -kA(dT/dx), where Q is the heat transfer rate, k is thermal conductivity, A is area, and dT/dx is the temperature gradient. Applications include heat loss through furnace walls and heat sinks in electronics.
  2. Convection: The transfer of energy between a solid surface and a moving fluid. It is governed by Newton's Law of Cooling: Q = hA(Ts - T∞), where h is the convective heat transfer coefficient, Ts is the surface temperature, and T∞ is the fluid temperature. Applications include cooling of engines and heat exchangers.
  3. Radiation: The transfer of energy via electromagnetic waves, requiring no medium. It is governed by the Stefan-Boltzmann Law: Q = εσA(Ts4 - Tsur4), where ε is emissivity, σ is the Stefan-Boltzmann constant, and Tsur is the surroundings temperature. Applications include solar energy collectors and space heating.
b

A long Cylindrical rod of radius 5 cm and K=10 W/m K, contains radio-active material which generates heat uniformly within the cylinder at a constant rate of 3 MW/m3. The rod is cooled by convection from its cylindrical surface into ambient air at 50°C with heat transfer coefficient of 60 W/m2 K. Calculate the temperature at the centre and outer surface of the cylindrical rod.

8 marks

Answer

Given: Radius R = 0.05 m, Thermal conductivity k = 10 W/m K, Heat generation q = 3 × 106 W/m3, Ambient temperature T∞ = 50°C, Convection coefficient h = 60 W/m2 K.

First, calculate the outer surface temperature (Ts) using the energy balance: Heat generated = Heat dissipated by convection.

q(πR2L) = h(2πRL)(Ts - T∞)
Ts = T∞ + (qR / 2h) = 50 + (3 × 106 × 0.05) / (2 × 60) = 50 + 1250 = 1300°C

Next, calculate the center temperature (T0) using the temperature distribution formula for a cylinder with uniform heat generation:

T0 = Ts + (qR2 / 4k)
T0 = 1300 + (3 × 106 × 0.052) / (4 × 10) = 1300 + 187.5 = 1487.5°C

The temperature at the outer surface is 1300°C and the temperature at the center is 1487.5°C.

2

What is critical radius of insulation? Derive the equation in spherical coordinate system.

15 marks

Answer

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3

Derive the equation for heat transfer rate and temperature distribution for a circular fin with insulated tip.

15 marks

Answer

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415 marks
a

How do the fluid properties influence the convective heat transfer? Explain the significance of convective heat transfer.

7 marks

Answer

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b

What are different non dimensional parameters influence the forced convection? Explain in detail about the non dimensional parameters.

8 marks

Answer

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5

Explain Von Karman integral momentum equation over a flat plate for the given velocity profile.

15 marks

Answer

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6

Draw the velocity and pressure profile over the cylinder for different Reynolds number and explain the significance.

15 marks

Answer

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7

What is meant by fouling factor of heat exchangers? Explain its effect on heat exchanger design.

15 marks

Answer

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815 marks
a

Determine the heat loss by radiation per meter length of 8 cm diameter pipe at 300°C if it is located in a large room with red brick walls at a temperature of 27°C. Emissivity of pipe is 0.79 and of brick is 0.93.

8 marks

Answer

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b

Explain the phenomenon film condensation over vertical cylinder and explain the salient features.

7 marks

Answer

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