JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech IV Year TRANSPORT PHENOMENA Previous Question Paper (October/November - 2020 - R16)

B.Tech | IV Year | I | R16 | October/November - 2020

Answer PaperPaper Code: 137HWMaximum Marks: 75Time: 2 hours

Answer any Five Questions. All Questions Carry Equal Marks.

Main

1

How does the viscosity vary with temperature and pressure for dilute gases and liquids?

15 marks

Answer

The viscosity of a fluid is a measure of its resistance to flow, and its dependence on temperature and pressure differs significantly between dilute gases and liquids due to differences in molecular structure and intermolecular forces.

1. Dilute Gases:

According to the kinetic theory of gases, the viscosity of a dilute gas is primarily a function of temperature and is largely independent of pressure, provided the pressure is not extremely high or low.

μ = (2/3πσ²) * √(mkT/π)

As temperature increases, the average molecular velocity increases, leading to a higher rate of momentum transfer between layers of gas, which results in an increase in viscosity. Mathematically, this is often expressed by the Sutherland formula or power-law models where viscosity is proportional to T^(1/2) or higher powers depending on the intermolecular potential model.

2. Liquids:

In liquids, molecules are closely packed, and viscosity is dominated by strong intermolecular cohesive forces rather than momentum transfer by molecular collisions. As temperature increases, the kinetic energy of the molecules increases, which helps them overcome these cohesive forces, leading to a decrease in viscosity. This is typically described by the Andrade equation:

μ = A * exp(B/T)

where A and B are constants specific to the liquid. Regarding pressure, the viscosity of liquids is generally independent of pressure at low to moderate values. However, at very high pressures, the viscosity of liquids increases significantly because the increased pressure reduces the free volume available for molecular movement, thereby hindering the flow process.

2

Derive an equation to calculate the velocity distribution in flow through circular tube.

15 marks

Answer

To derive the velocity distribution for steady, laminar, fully developed flow of an incompressible Newtonian fluid through a horizontal circular tube of radius R and length L, we perform a shell momentum balance on a cylindrical shell of fluid at radius r with thickness Δr and length L.

The momentum balance states that the rate of momentum in minus the rate of momentum out plus the sum of forces acting on the system equals zero. For steady flow, the momentum flux balance simplifies to the equality of pressure forces and viscous forces:

P₀(πr²) - Pᴸ(πr²) + τᵣᵣ(2πrL) = 0

Dividing by 2πrL and rearranging for the shear stress τᵣᵣ:

τᵣᵣ = (P₀ - Pᴸ)r / 2L

Using Newton's law of viscosity, τᵣᵣ = -μ(dvᶻ/dr), where μ is the dynamic viscosity and vᶻ is the velocity in the axial direction:

-μ(dvᶻ/dr) = (ΔP/L)(r/2)

Separating variables and integrating with respect to r:

dvᶻ = -(ΔP / 2μL)r dr
vᶻ = -(ΔP / 4μL)r² + C

Applying the no-slip boundary condition at the wall, where vᶻ = 0 at r = R, we find the constant of integration C:

0 = -(ΔP / 4μL)R² + C ⇒ C = (ΔP / 4μL)R²

Substituting C back into the velocity equation yields the final parabolic velocity distribution:

vᶻ(r) = (ΔP R² / 4μL) [1 - (r/R)²]

This result shows that the velocity profile is parabolic, with the maximum velocity occurring at the centerline (r = 0).

3

Derive the velocity distribution (Vz) equation in a falling film.

15 marks

Answer

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4

Develop the temperature profile equation when heat conduction occurs in a cooling fin?

15 marks

Answer

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5

Consider a spherical porous catalyst. A gas stream in contact with the catalyst contains reactant A which diffuses into the catalyst pellet and reacts at the internal surface of the catalyst to form product B. The gas film surrounding the catalyst does not offer any resistance. Find out the effectiveness factor of the catalyst.

15 marks

Answer

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6

Develop the concentration profile for diffusion with a homogeneous chemical reaction.

15 marks

Answer

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7

Derive time smoothed equations of change for an incompressible fluid?

15 marks

Answer

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815 marks
a

Explain about the equation of motion.

7 marks

Answer

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b

Write about substantial derivative?

8 marks

Answer

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About this paper

This page contains the question paper of TRANSPORT PHENOMENA from JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD for B.Tech PTM IV Year I, October/November - 2020, R16.

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