JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD Pharm. D I Year REMEDIAL MATHEMATICS Previous Question Paper (September/October - 2021 - R08)

Pharm. D | I Year | I Year | R08 | September/October - 2021

Answer PaperPaper Code: PH106Maximum Marks: 70Time: 3 Hours

Answer any five questions

All questions carry equal marks

Main

114 marks
a

Solve: 2x + 3x + 4x = 0; 2x + 3x + 4x = 0; 2x + 3x + 4x = 0

7 marks

Answer

The given equations are 2x + 3x + 4x = 0, which simplifies to 9x = 0. Since this equation is identical for all three instances, the system reduces to a single linear equation in one variable: 9x = 0. Dividing both sides by 9 gives x = 0. As there are no constraints provided for y or z, the system is underdetermined, resulting in a solution set where x = 0 and y, z can be any real numbers.

b

Solve the following system of equations by Cramer’s rule: x – y + 2z = 7, 3x + 4y – 5z = –5, 2x – y + 3z = 12.

7 marks

Answer

To solve the system using Cramer's rule, we first calculate the determinant of the coefficient matrix D:

D = |1 -1 2; 3 4 -5; 2 -1 3| = 1(12 - 5) - (-1)(9 - (-10)) + 2(-3 - 8) = 7 + 19 - 22 = 4

Next, we calculate the determinants Dx, Dy, and Dz by replacing the respective columns with the constants column (7, -5, 12):

Dx = |7 -1 2; -5 4 -5; 12 -1 3| = 7(12 - 5) + 1(-15 + 60) + 2(5 - 48) = 49 + 45 - 86 = 8
Dy = |1 7 2; 3 -5 -5; 2 12 3| = 1(-15 + 60) - 7(9 + 10) + 2(36 + 10) = 45 - 133 + 92 = 4
Dz = |1 -1 7; 3 4 -5; 2 -1 12| = 1(48 - 5) + 1(36 + 10) + 7(-3 - 8) = 43 + 46 - 77 = 12

Finally, the values of the variables are determined by dividing these determinants by D:

x = Dx / D = 8 / 4 = 2
y = Dy / D = 4 / 4 = 1
z = Dz / D = 12 / 4 = 3

The solution is x = 2, y = 1, z = 3.

214 marks
a

If a = 18, b = 24 and c = 30 then find sin A, sin B and sin C.

7 marks

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b

If tan(A-B) = 7/24 and tan A = 4/3, then find A+B.

7 marks

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314 marks
a

Find the equation of the line passing through the point (-2, 2) and the sum of the intercepts on the coordinate axes is 3.

7 marks

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b

Find the equation of the circle passing through the point (2, -1) and whose centre is (2, 3).

7 marks

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414 marks
a

Find the derivative of the function y = (1 + 2sec x) / (2 + 5sec x)

7 marks

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b

If z = xy + 3sin x - 4cos y + 1, then find ∂z/∂x and ∂z/∂y.

7 marks

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514 marks
a

Evaluate the integral of x^2 * e^(3x) dx.

7 marks

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b

Evaluate the integral of dx / (4sin^2 x + 5cos^2 x).

7 marks

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614 marks
a

Evaluate the integral from 0 to π/2 of (cos x / (1 + sin x)) dx.

7 marks

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b

Solve the differential equation dy/dx + (x - y)e^x = y^2 e^x.

7 marks

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714 marks
a

Solve the differential equation (x^2 - 4xy - 2y^2)dx + (y^2 - 4xy - 2x^2)dy = 0.

7 marks

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b

Solve the linear differential equation dy/dx + (2x/(1+x^2))y = (x^2 + 4)/(1+x^2).

7 marks

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814 marks
a

Find L{t^2 + 3e^(4t) - 2sin3t}.

7 marks

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b

State and prove first shifting theorem.

7 marks

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About this paper

This page contains the question paper of REMEDIAL MATHEMATICS from JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD for Pharm. D I Year I Year, September/October - 2021, R08.

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