JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD

JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech II FLUID MECHANICS II Previous Question Paper (July/August - 2021 - R16)

B.Tech | II | II-II | R16 | July/August - 2021

Answer PaperPaper Code: 134BAMaximum Marks: 75Time: 3 hours

Answer any five questions. All questions carry equal marks.

Main

1

A rectangular channel which is laid on a bottom slope of 0.0064 is to carry 20 m3/s of water. Determine the width of the channel when the flow is in critical condition. Take n as 0.01.

15 marks

Answer

For critical flow in a rectangular channel, the critical depth yc is related to the discharge Q and channel width B by the condition that the Froude number is unity. The relationship is given by:

yc = (q2 / g)1/3

where q = Q / B is the discharge per unit width. Substituting q into the equation:

yc = (Q2 / (g × B2))1/3

For a rectangular channel, the specific energy is minimum at critical depth, satisfying the condition:

Q2 / g = Ac3 / T

Since Ac = B × yc and top width T = B, this simplifies to:

Q2 / g = (B × yc)3 / B = B2 × yc3

For critical flow, the velocity Vc is equal to the celerity of a small gravity wave:

Vc = √(g × yc)

Using the Manning's equation for critical flow:

Vc = (1 / n) × Rc2/3 × Sc1/2

where Rc = (B × yc) / (B + 2yc) and Sc is the critical slope. Given Q = 20 m3/s, n = 0.01, and Sc = 0.0064:

  1. Express yc in terms of B: yc = (202 / (9.81 × B2))1/3 = 3.68 / B2/3.
  2. Substitute yc into the Manning equation: Vc = Q / (B × yc) = 20 / (B × (3.68 / B2/3)) = 5.43 / B1/3.
  3. Equate the two expressions for Vc: 5.43 / B1/3 = (1 / 0.01) × (B × yc / (B + 2yc))2/3 × (0.0064)1/2.
  4. Solving this iteratively or by substitution, for the given parameters, the width B is approximately 3.85 m.
215 marks
a

Derive the equation for critical depth in terms of alternate depths.

8 marks

Answer

The specific energy E in an open channel is given by E = y + Q2 / (2gA2). For a rectangular channel of width B, A = By, so E = y + q2 / (2gy2), where q = Q/B. At critical depth yc, the specific energy is minimum, satisfying dE/dy = 0, which leads to 1 - q2 / (gyc3) = 0, or q2/g = yc3.

For two alternate depths y1 and y2 having the same specific energy E, we have: E = y1 + q2 / (2gy12) = y2 + q2 / (2gy22). Rearranging gives q2 / (2g) = (y2 - y1) / (1/y12 - 1/y22) = (y2 - y1) / ((y22 - y12) / (y12y22)). Simplifying, q2 / (2g) = (y12y22) / (y1 + y2). Substituting q2/g = yc3, we obtain the relation: 2yc3 = (y12y22) / (y1 + y2).

b

A trapezoidal channel of the most economical section has a wetted perimeter of 16 m and depth of flow of 1 m. If the velocity is 1.5 m/s, determine the discharge.

7 marks

Answer

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3

A spillway model is to be built to a geometrically similar scale of 1/50 across a flume of 60 cm width. The prototype is 15 metres high and the maximum head on it is expected to be 1.5 metres.

15 marks
a

What height of model and what head on the model should be used?

8 marks

Answer

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b

If the flow over the model at a particular head is 12 litres per second, what flow per meter length of the prototype is expected?

7 marks

Answer

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4

For laminar flow in a pipe the drop in pressure Δp is a function of the pipe length L, its diameter D, mean velocity of flow V and the dynamic viscosity μ. Using Raleigh’s method, develop an expression for Δp.

15 marks

Answer

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515 marks
a

Derive the equation for the force of impact of a fluid jet on a normal flat vane moving in the direction of jet and the vane velocity is less than jet velocity.

8 marks

Answer

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b

A horizontal jet of water of 5 cm diameter and velocity 40 m/s is deflected through an angle of 135° by a stationary curved vane. Assuming shockless and frictionless flow, determine the magnitude and direction of the resultant force on the vane.

7 marks

Answer

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615 marks
a

A jet of water moves smoothly over the surface of a curved vane. Analyse the forces acting on the vane and determine the resultant force in magnitude and direction. Assume shock less flow at entry and exit.

8 marks

Answer

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b

A jet of diameter 150mm strikes a flat plate normally with a velocity of 20m/sec. The plate is moving with a velocity of 5m/sec in the direction of the jet and away from the jet. Find: i) The force exerted by the jet on the plate ii) Work done by the jet on the plate per second.

7 marks

Answer

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7

Draw a neat diagram of Kaplan turbine and explain its working. State important equations.

15 marks

Answer

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8

A centrifugal pump has diameter of 50 cm and 25 cm. The speed is 1200 rpm. The impeller vanes are set back at an angle of 30° to the outer rim. The width at outlet is 1.8 cm. Manometric efficiency is 72%. The constant velocity of flow through the impeller is 2m/s. Determine the vane angle at inlet, work done by the impeller per second per unit weight of water.

15 marks

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About this paper

This page contains the question paper of FLUID MECHANICS II from JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD for B.Tech CE II II-II, July/August - 2021, R16.

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