JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD
JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY HYDERABAD B.Tech II Year STRUCTURAL ANALYSIS I Previous Question Paper (August/September 2022 - R15)
Answer any Five Questions. All Questions Carry Equal Marks.
Main
Determine the forces induced in the members BC, CG and EF of the pin-jointed truss shown in the Figure 1.
Answer
To determine the forces in members BC, CG, and EF of a pin-jointed truss, we employ the Method of Sections. This method involves cutting the truss through the members of interest and applying the conditions of static equilibrium to one of the resulting segments.
1. Global Equilibrium: First, calculate the support reactions at the external supports (typically pins or rollers) by applying the equations of static equilibrium for the entire truss: ΣFx = 0, ΣFy = 0, and ΣM = 0.
2. Section Selection: Pass a section line through members BC, CG, and EF. This section divides the truss into two parts. Choose the part that is simpler to analyze or has fewer external forces.
3. Equilibrium of the Section: Apply the three equations of equilibrium to the chosen segment:
4. Calculation: By taking moments about a point where two of the unknown member forces intersect, the third unknown force can be determined directly. Repeat this process for the other members. Tension is indicated by a positive result, while compression is indicated by a negative result.
5. Verification: Ensure that the internal forces calculated satisfy the equilibrium of the joints connected to these members to verify the accuracy of the section analysis.
Determine the force in each member of the loaded truss by Method of Joints shown in figure 2.
Answer
To determine the forces in each member of the truss using the Method of Joints, follow these steps:
- Calculate Support Reactions: Determine the external reactions at the supports by applying the equations of static equilibrium: ∑Fx = 0, ∑Fy = 0, and ∑M = 0.
- Identify Zero-Force Members: Inspect the joints to identify members with zero internal force, typically where two non-collinear members meet at an unloaded joint or where three members meet at a joint with two being collinear and no external load applied.
- Select a Joint: Start at a joint with at most two unknown member forces.
- Apply Equilibrium Equations: At the chosen joint, resolve all forces into horizontal and vertical components. Apply ∑Fx = 0 and ∑Fy = 0 to solve for the two unknown member forces.
- Proceed to Adjacent Joints: Move to the next joint where there are now only two unknown forces, using the values calculated from previous joints.
- Determine Nature of Force: If the calculated value is positive, the member is in tension; if negative, the member is in compression.
Repeat this process until the forces in all members are determined. Ensure that the final joint satisfies equilibrium as a check for the calculations.
Figure 3 shows a three hinged parabolic arched rib ACB with supports at different levels. It has a horizontal span of 15 m, the hinge at the crown C being at 6m horizontally from A and 2 m vertically above it. Calculate the difference between the levels of the supports A and B. The arch carries an UDL of 15 kN/m from A to C. Calculate the horizontal thrust and negative B.M.
Answer
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A Fixed beam AB of span 6.0m carries point loads 150KN and 200KN as shown in Figure 4. If the left and the right supports sink by 15mm and 7mm respectively, find the fixing moments at the supports. Find also the reactions at supports. Draw also the BMD for the beam. Take EI=6000KN-m2.
Answer
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ABC is a continuous beam with constant EI throughout its length. The end supports A and C are fixed and beam is continuous over middle support B. Span BC is 4.0m long carrying uniformly distributed load of intensity 10kN per meter length, while a concentrated vertical load of 100kN acts at the mid span AB of 6.0m length. Calculate the moments by slope deflection method. Draw BMD.
Answer
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Analyse the continuous beam by Moment Distribution Method shown in figure 5. Draw BMD and Elastic curve.
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A train of loads shown in Figure 6 moves from left to right on a simply supported girder AB of span 16m. Determine the absolute maximum shear force and bending moment developed in the beam.
Answer
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An udl of intensity 5kN/m and 6 m long crosses a simply supported beam of 25 m span from left to right. Calculate:
The maximum shear force and bending moment at section 10 m from the left support.
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Absolute maximum bending moment.
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