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JNTU B.Tech II ELECTROMAGNETIC FIELDS Previous Question Paper (March - 2022 - R16)

B.Tech | II | I | R16 | March - 2022

Answer PaperPaper Code: 133APMaximum Marks: 75Time: 3 Hours

Answer any five questions. All questions carry equal marks.

Main

115 marks
a

Derive the expression for Electric Field due to Sheet of charge.

7 marks

Answer

Consider an infinite sheet of charge in the xy-plane with a uniform surface charge density ρs (C/m2). By symmetry, the electric field must be directed normal to the sheet, i.e., in the ±z direction. Applying Gauss's Law to a Gaussian pillbox extending from z = -h to z = h with cross-sectional area A:

∮ D · dS = Qenclosed

The flux through the side walls is zero since the field is parallel to the walls. The flux through the two end caps is:

2 × (Dz × A) = ρs × A

Solving for the electric field intensity E = D/ε0:

E = (ρs / 2ε0) an

where an is the unit vector normal to the sheet, pointing away from the surface.

b

A charge Q2 = 121 nC is located in vacuum at P2(-0.03, 0.01, -0.04). Find force on Q2 due to Q1 = 100 µC at P1(0.03, 0.08, 0.02). All distances in meters.

8 marks

Answer

Given Q1 = 100 × 10-6 C at P1(0.03, 0.08, 0.02) and Q2 = 121 × 10-9 C at P2(-0.03, 0.01, -0.04). The distance vector r12 from P1 to P2 is:

r12 = (-0.03 - 0.03)ax + (0.01 - 0.08)ay + (-0.04 - 0.02)az = -0.06ax - 0.07ay - 0.06az

The magnitude |r12| is:

|r12| = √((-0.06)2 + (-0.07)2 + (-0.06)2) = √(0.0036 + 0.0049 + 0.0036) = √0.0121 = 0.11 m

Using Coulomb's Law, the force F on Q2 is:

F = (Q1Q2 / 4πε0|r12|3) r12

Substituting the values (1/4πε0 ≈ 9 × 109):

F = (9 × 109 × 100 × 10-6 × 121 × 10-9 / (0.11)3) × (-0.06ax - 0.07ay - 0.06az)
F = (0.1089 / 0.001331) × (-0.06ax - 0.07ay - 0.06az) ≈ 81.82 × (-0.06ax - 0.07ay - 0.06az)
F = -4.91ax - 5.73ay - 4.91az N
215 marks
a

What is the significance of Laplace’s Equation? Also obtain the solution of Laplace’s equation in one variable.

7 marks

Answer

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b

Derive the expression for torque on a electric dipole in a electrostatic field.

8 marks

Answer

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315 marks
a

Define capacitance and derive the expression for the capacitance of Co-axial capacitor with composite dielectric.

7 marks

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b

State and explain about Ohm’s law in Point form.

8 marks

Answer

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415 marks
a

Obtain the expression for MFI due to Solenoid in a current carrying wire by applying Biot-Savort’s law.

8 marks

Answer

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b

A current element I·Δl = 2π(0.6ax - 0.8ay) is situated at a point (4, -2, 3). Find the incremental field at ΔH at point (1, 2, 3).

7 marks

Answer

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515 marks
a

State and explain Ampere Circuital Law with any one application.

8 marks

Answer

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b

Explain about Point form of Ampere Circuital law.

7 marks

Answer

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615 marks
a

Explain how a differential current loop acts as magnetic dipole.

7 marks

Answer

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b

Derive the expression for Force between two straight long and parallel current carrying conductor.

8 marks

Answer

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715 marks
a

What is polarization? Explain.

7 marks

Answer

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b

Obtain the boundary conditions for dielectric-dielectric media in electrostatic fields?

8 marks

Answer

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815 marks
a

Write the Modified Maxwell’s equations for time varying fields.

7 marks

Answer

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b

Explain Faraday’s laws of electromagnetic Induction.

8 marks

Answer

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